How much 30 index fluid is needed to make 1 gallon of a 2% solution?

To find out how much of a 30 index fluid is needed to create a 2% solution, we first need to understand what a 2% solution means. A 2% solution means that there are 2 grams of the solute (in this case, the 30 index fluid) for every 100 milliliters of solution.

Since 1 gallon is approximately 3,785 milliliters, a 2% solution in 1 gallon would require:

[

\text{Amount of solute} = \frac{2 \text{ g}}{100 \text{ mL}} \times 3,785 \text{ mL} \approx 75.7 \text{ g}

]

Next, we need to determine how much of the 30 index fluid corresponds to this mass, given that the fluid has a specific gravity of approximately 1. This means 30 index fluid is near the density of water, where 1 mL has a mass of about 1 g.

To convert 75.7 grams of the 30 index fluid into ounces, knowing there are about 28.35 grams in an ounce:

[

\text{Ounces} = \